3x^2+6x+3-2(x+1)+5=0

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Solution for 3x^2+6x+3-2(x+1)+5=0 equation: 



3x^2+6x+3-2(x+1)+5=0

We add all the numbers together, and all the variables

3x^2+6x-2(x+1)+8=0

We multiply parentheses

3x^2+6x-2x-2+8=0

We add all the numbers together, and all the variables

3x^2+4x+6=0

a = 3; b = 4; c = +6;
Δ = b2-4ac
Δ = 42-4·3·6
Δ = -56
Delta is less than zero, so there is no solution for the equation

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